Question

A can finish a piece of work in 20 days alone If B is 10% more efficient than A
how many days will A and B together take to finish the same piece of work?​

Answer 1

Answer:

an example I am not giving you the answer so please don't copy it the answer just

appreciate it ok .

explanation

A can do a piece of work in 18 days, B is 50% more efficient than A. The number of days B will take to do the same piece of work is?

Efficiency is inversely proportional to the no of days needed to do the work.

More efficiency means less no of days needed to complete the work.

If efficiency of A is 100, then efficiency of B is 50% more that is 150. The ratios of efficiency of A and B is

A/B (efficiency) =100/150 =2/3

A completes the work in 18 days n let B complete the work in x days. The ratio of no of days needed to complete the work by A and B is

A/B (days) = 18/x

Now efficiency is inversely proportional to no of days so A/B is

2/3 (efficiency ) = x /18 (days)

3×x =2×18

x = 12 days

B would complete the work in 12 days.