Question

a can finish a piece of work in 30 days.he worked alone for 6 days and b joined him. together they could finish the remaining work in 9 days.in how many days b alone can finish the same piece of work?​

Answer 1

Answer:

A- 30 days for full work; 1 day: 1/30 work.

6 days: 6/30 work done; 6/30 is 1/5.

Remaining work:4/5

Together done in 9 days.

Together in one day: (4/5)÷9=4/45=8/90

Done by A in one day: 1/30=3/90

Done by B in one day=(8/90)-(3/90)=(8–3)/90=5/90=1/18

B does 1/18 work per day: so 18 days required to complete work alone.

Ans: 18 days.

Answer 2

Step-by-step explanation:

A worked for total 6+9= 15 days

Work done = 15/30= 1/2

Remaining work = 1/2 done by B in 9 days

So B alone = 18 days ANSWER