A can finish a work 18 Days . B is twice as efficient as A . if they work together in how many days the work will be completed ?
Answers
Answer:
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Step-by-step explanation:
Given,
A is twice as efficient as B and together they can finish a work in 18 days.
Formula used:-
Men x Day Total work
Calculation:-
According to the question,
A = 2B
A/B = 2/1
→ Total work = (2+1)x 18
→ 54
A alone can finish the work
→ 54/2
→ 27
:: A alone can finish the work in 27 days.
Answer: The work will be completed in 6 days if A and B work together.
Step-by-step explanation:
A can finish a work in 18 days.
B is twice as efficient as A, means A=2B
A=2B=18days
2B= 18
B=18/2=9 days
so B can finish the same work in 18 days / 2 = 9 days.
When they work together, their combined rate of work is 1/9 + 1/18.
To find the time it takes for them to finish the work together, we can use the formula: time = work / rate of work.
By substituting the values, we get: time = 18 days / (1/9 + 1/18) = 6 days.
Therefore, the work will be completed in 6 days if A and B work together.
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