A can finish a work in 12 days and B can do it in 15 days,after A had worked for 3 days, B also joined A to finished the remaining work in how many days the remaining work will be finished.
Answers
Answer:
5 days
Step-by-step explanation:
A can do work in days = 12
A's 1 day work =
A's 3 days work =
Remaining work =
B can do work in days = 15
B's 1 day work =
(A+B)'s 1 day work =
(A+B)'s 1 day work =
A+B can do work in days = 1
A+B can do work in days =
A+B can do work in days =
Hence Remaining work can be done in 5 days
Step-by-step explanation:
5 days
Step-by-step explanation:
A can do work in days = 12
A's 1 day work = \frac{1}{12}
12
1
A's 3 days work = \frac{3}{12} =\frac{1}{4}
12
3
=
4
1
Remaining work = 1-\frac{1}{4} = \frac{3}{4}1−
4
1
=
4
3
B can do work in days = 15
B's 1 day work = \frac{1}{15}
15
1
(A+B)'s 1 day work = \frac{1}{15}+\frac{1}{12}
15
1
+
12
1
(A+B)'s 1 day work = \frac{1}{15}+\frac{1}{12}=\frac{3}{20}
15
1
+
12
1
=
20
3
A+B can do \frac{3}{20}
20
3
work in days = 1
A+B can do work in days = \frac{20}{3}
3
20
A+B can do\frac{3}{4}
4
3
work in days = \frac{20}{3} \times \frac{3}{4}=5
3
20
×
4
3
=5
Hence Remaining work can be done in 5 days