Math, asked by shuebkhan533, 7 months ago

A can finish a work in 15 days and B can fiish it in 60 days. B worked for 10 days and left the job. in how many days A alone can finish the remaining work?​

Answers

Answered by gbkluggage
4

Step-by-step explanation:

none , it is already built that too 2 times

Answered by khanshamshad62489
0

Step-by-step explanation:

A can finish work in 18 days.

It means A can do the work in one day = 1/18 part

B can finish it in 15 days.

It means B can do the work in one day = 1/15 part

B worked alone for 10 days and then left the job

Thus in 10 days B has completed part of work =

1/15 × 10 = 10/15 part or 2/3 part of work

Remaining work left = 1 - 2/3 = 1/3 part of work remaining

A can do 1/18 part in one day

Therefore 1/3 part will be completed by him

= 1/1/18 × 1/3

= 1/3 × 18/1

= 18/3 days

= 6 days

A alone will complete the work in 6 days

Similar questions