A can finish a work in 20 days, while B can finish it in 12 days. A started the work alone and after 4 days B joined him and they work together till the work was completed. For how long did they work together?
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Answer:
Step-by-step explanation:
Work by A in 1 day = 1/20
Work by B in 1 day = 1/12
Together they work = (1/20)+(1/12) = (3 + 5)/60 = 8/60 = 2/15
Total time taken by them = 7.5 days
But here A work 5 days alone.
Work by A in 5 days = (3/60)×5 = 15/60
Let x be the number of days they work after.
After that they work together,
(15 + × (3+8))/60 = 1
8x = 60 - 15
x = 45/8
x = 5(5/8) days
Total time taken = 5 + 5 (5/8) = 10 (5/8)days
sujalxdx:
wrong
answer is 6 days
plz reply
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please give me a brainlist answer
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