A can finish a work in 24 days and b can finish the same work in 18 days if they work together for 4 days and b left and then how many days are required to complete the work by a
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A B
24 18
Total Work=LCM(24 , 18) = 72 units
3 4
Work completed by A in 1 day = 3 units
Work completed by B in 1 day = 4 units
Work completed by A + B in 1 day = 7 units
Let the number of days in which A complete the remaining work be x days
According to the question :
(A+B) * 4 + A * x = 72
7 * 4 + 3x = 72
3x = 72 - 28
x = 44/3 days
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shantanurauthan:
Np,would you mind marking this answer as brainliest ?Only if you understood
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