A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:
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A's one day work=1/24
B's one day work=1/9
C's one day work=1/12
(B+C)'s one day work=1/9+1/12=4+3/36=7/36
(B+C)'s work in three days=7/36*3=7/12
Amount of work left=1-7/12=5/12
A does one part work in 24 days
Therefore, A does 5/12 part of the work in=5/12*24=10 days
Answer=10 days
B's one day work=1/9
C's one day work=1/12
(B+C)'s one day work=1/9+1/12=4+3/36=7/36
(B+C)'s work in three days=7/36*3=7/12
Amount of work left=1-7/12=5/12
A does one part work in 24 days
Therefore, A does 5/12 part of the work in=5/12*24=10 days
Answer=10 days
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