A can finish a work in 24 days. B is 20℅ more efficient than A. C is 5℅ more efficient than B. in how many days B and C together can finish the same piece of work
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days=24
B+C=20%+5%
=25%
24×25/100
=6
days=24+6=30
B+C=20%+5%
=25%
24×25/100
=6
days=24+6=30
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