A can finish a work in 27 days and B can do the same work in 18 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
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Answered by
1
Answer:
12 days
Step-by-step explanation:
A can finish work in 27 days.,
It means A can do the work in one day = 1/27 part
B can finish it in 18 days.,
It means B can do the work in one day = 1/18 part
B worked alone for 10 days and then left the job ,
Thus in 10 days, B has completed part of work =
1/18 × 10 = 10/18 part or 5/9 part of work.
Remaining work left = 1 - 5/9 = 4/9 part of work remaining .
A can do 1/27 part in one day ,
∴ 4/9 part will be completed by him
= 1/1/27 × 4/9
= 4/9× 27/1
=108/9
=12
A alone will complete the work in 12 days .
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Answered by
2
Answer:
12 days
Step-by-step explanation:
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