A can finish a work in 40 .B is 25 percent less efficient than A .A number of days A and B Will take to finish the work together
Answers
Answer:
Let Total Work = 100 units
A can complete 100 units in 21 days
Since B is 40% more efficient, he can complete 140 units in 21 days.
=> B can complete 100 units in :
21/140 x 100 = 15 days
Step-by-step explanation:How do we calculate efficiency of B w.r.t. A ?
I think it’s this way -
Efficiency is output/ input.
If input is same, more efficiency means more output.
In this case, input is time and output is work.
B , being 40% more efficient than A, should produce 40% more work in a given time.
So in 21 days, work done by B = 1.4 (40% more than A)
So, time taken by B to finish 1 work(means same as A) = 21/1.4 =15 days.
Answer:32
Step-by-step explanation:
efficiency is inversly prortional to work done
thus B will take 4/3 times the number of days A will take.....
just like parallel connection of resistances add the reciprocal of
the no. of days each would take and take the reciprocal of this result.....