Question

A can finish a work in 40 .B is 25 percent less efficient than A .A number of days A and B Will take to finish the work together

Answer 1

Answer:

Let Total Work = 100 units

A can complete 100 units in 21 days

Since B is 40% more efficient, he can complete 140 units in 21 days.

=> B can complete 100 units in :

21/140 x 100 = 15 days

Step-by-step explanation:How do we calculate efficiency of B w.r.t. A ?

I think it’s this way -

Efficiency is output/ input.

If input is same, more efficiency means more output.

In this case, input is time and output is work.

B , being 40% more efficient than A, should produce 40% more work in a given time.

So in 21 days, work done by B = 1.4 (40% more than A)

So, time taken by B to finish 1 work(means same as A) = 21/1.4 =15 days.

Answer 2

Answer:32

Step-by-step explanation:

efficiency is inversly prortional to work done

thus B will take 4/3 times the number of days A will take.....

just like parallel connection of resistances add the reciprocal of

the no. of days each would take and take the reciprocal of this result.....