Math, asked by paulshuvra, 1 year ago

A can finish a work in 5 days and B takes 4 days to do the same work. If the work is increased by 8 times, how many days will it take for both of them to finish the work if they work together?

Answers

Answered by ivarun
6

Answer:

A takes 5 days and B takes 4 days to compete the work.

Let's say total work is 20 units (which can be easily cancelled by 5 & 4)

So the rate of work of A= 20/5 =4 units per day

Rate of work for B= 20/4 = 5 units per day

Together they can do 5+4= 9 units per day.

Now we assumed total work as 20 units in beginning. Just increase it 8 times.

New total work= 20*8 = 160 units

Therefore, they will take 160/9 days or 17.77 days or 17 days and 18 hours or 18 days approx.

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