Math, asked by Rijudiptanil, 5 months ago

a can finish painting a house in 6 days and B can finish painting the same house in 10 days on April 1 they started painting the house together after painting for 3 days a cannot continue working and B has to finish painting the house alone on which day will the house be fully painted?​

Answers

Answered by Abhinavaps
2

Answer:

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Answered by akp3039Karthikeyan
1

Answer:

let total work done =1

kavita finish in 1 day= 1/6 work

anitah '''''''''''''''= 1/10 work

after 3 days total work done by both together = (3/6)+(3/10)= 4/5

work to be done left= 1-4/5= 1/5

kavita takes time to do 1/5 work= 6*1/5 day= 1.2 days

therefore work finished on 5th april7 years agoHelpfull: Yes(3) No(0)the house is fully painted on 5th april

kavitha can paint in 1 day= 1/6 and for anitha its 1/10 so after 3 day they combenely paint 3/6+3/10=4/5 so the work left =1/5 and it have to be completed by anitha..so she can complete it in 10*1/5=2 days..

so total no of days required=3+2=5.

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