Question

A can finish the job in 25 days and B can finish it in 30 days. After working together for 4 days, A leaves the job. In what time will B finish the remaining job, working alone?
GIVE ANSWER WITH STEPS​

Answer 1

Answer:

and B do 5[(1/25)+(1/30)] = 5*(30+25)/(25*30) = (5*55/750) = (1/2.7)th of the work in 5 days. After 5 days when A leaves the work, the work remaining is (1.7/2.7)th of the work.

The remaining work can be done by B alone in (1.7/2.7)/(1/30)

= 1.7*30/2.7

= 18.9 days.

Answer 2

A's WORK=$\frac{1}{25}$

B's WORK=$\frac{1}{30}$

A's AND B's TOGETHER 1 DAY's WORK

$\frac{1}{25}+\frac{1}{30}$=$\frac{11}{150}$+$\frac{4}{150}$=$\frac{11+4}{150}$=$\frac{15}{150}$

NOW THE REMANING WORK DONE BY B

LET B TAKES X DAY TO COMPLETE THE WORK

$\frac{1}{30}*X=\frac{15}{150}$

$X=\frac{15}{150}*30$

X=3

HENCE B WILL TAKE 3  DAYS TO COMPLETE WORK