A can finish the work in 15 days, b in 18 days and c in 20 days. B and c starts the work together and are found to leave after 4 days. Then what is the time taken to finish the remaining work.
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Answer:
Step-by-step explanation:
Let the total work is 180 unit
Work done by A in one day = 12 unit
Work done by b in one day = 10 unit
Work done by sea in one day = 9 unit
B+C= 19 unit for four days 76 unit by both
Total 180
Remaining work 180-76=104 unit
time taken by a = 104/12 days
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