A can give B a start of 20m and C a start of 39 m in 400 m race .how much start can B give C
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Just find B first then with the value of B find the value of C
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Given:
A can give B a start of 20m
A can give C a start of 39m
Total distance both are travelling = 400m
To Find:
How much start B can give to C
Solution:
(L - x12)x23 = L(x13 - x12)= (400 - 20)x23 = 400(39 - 20)= x23 = 20 metres
Thus, B can give a start of 20m to C.
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