Question

A can have a piece of work in 8 days, B can work 3 times faster than A. C can do work 5 time faster than A .How many days they will do work together.​

Answer 1

Answer:

Let efficiency of A - 1 units

so, efficiency of B - 3 units

efficiency of c - 5 units

If A can complete a piece of work in 8 days so total work will br 8 ×1 = 8 units.

And , Total efficiency of A+B+C = 9 units..

If all three together do the work the will be completed in = 8/9 Days...