Math, asked by ramidas2001, 8 months ago

A can hit a tanget 3 times out of 4 attempts, B can hit a target 4 times out of 5 attempts. Each is allowed to shoot once. What is the probability that thetarget is hit ?​

Answers

Answered by rajrsharma2007
0

Answer:

Fire a volley means that A,BandC all try to hit the target simultaneously.

Two shots hit the target in one of the following ways:

(1) A and B hit and C fails to hit.

(2) A and C hit and B fails to hit.

(3) B and C hit and A fails to hit.

The chance of hitting by A,P(A)=

5

4

and of not hitting by him P(A

)=1−

5

4

=

5

1

.

The chance of hitting by B,P(B)=

4

3

and of not hitting by him P(B

)=1−

4

3

=

4

1

.

The chance of hitting by C,P(C)=

3

2

and of not hitting by him P(C

)=1−

3

2

=

3

1

.

The probability of (1) is P(ABC

)=

5

4

×

4

3

×

3

1

=

5

1

.

The probability of (2) is P(ACB

)=

5

4

×

3

2

×

4

1

=

15

2

.

The probability of (3) is P(BCA

)=

4

3

×

3

2

×

5

1

=

10

1

.

Thus the probability that two shots hit the target is

5

1

+

15

2

+

10

1

=

30

13

.

Step-by-step explanation:

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