A can hit a target 3 times in 5 shots. B 2 times in 5 shots and C 3times in 5 shots. They fire a volley. What is the probability that (i) two shots hit the target (ii) one shots hit the target?
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P(A) = 3/5 , P(B) = 2/5 and P(C) = 3/4
That means P(A') = 2/5 P(B') =3/5 and P(C') = 1/4
A and B hit but not C= 3/5 * 2/5 * 1/4 = 3/50 = 6/100
A and C hit but not B = 3/5 * 3/4 * 3/5 = 27/100
B and C hit but not A = 2/5 * 3/4 * 2/5 = 3/25= 12/100
So total probability is all 3 added = (6+27+12) /100= 45/100 = 9/20= 45% 2 out of 3 hit the
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