A can hit a target 3 times out of 5 trials,B can hit the target 2 times out of 5 trials; C can hit the target 3 times out of 4 trials. if all the three try simultaneously find the probability that at least 2 will hit the target.
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Answer:
P(A) = 3/5 , P(B) = 2/5 and P(C) = 3/4
That means P(A') = 2/5 P(B') =3/5 and P(C') = 1/4
A and B hit but not C= 3/5 * 2/5 * 1/4 = 3/50 = 6/100
A and C hit but not B = 3/5 * 3/4 * 3/5 = 27/100
B and C hit but not A = 2/5 * 3/4 * 2/5 = 3/25= 12/100
So total probability is all 3 added = (6+27+12) /100= 45/100 = 9/20= 45% 2 out of 3 hit the
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