Question

a can of coffee has a net weight of 200 grams find the smallest number of cans that must be purchased to have atleast 8kg of coffee

Answer 1

Answer:

40

Step-by-step explanation:

Total desired weight of coffee = 8 kg

Net weight of 1 can = 200 g

Number of cans required = 8 kg ÷ 200 g

1 kg = 1000 g

8 kg = 8000 g

8000 ÷ 200 = 40

Therefore, number of cans required = 40