A can of paint contains 1000ml of certain paint, which is sufficient for painting an area of 10 m2. How many cans will be sufficient to paint a rectangular wall on one side which is 10m long and 7m high.
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Answered by
0
Given:
⇒Area=9.375m
2
⇒22.5cm×10cm×7.5cm=l×b×h
⇒Total surface of cuboid (brick) =2(lb+bh+lh)
⇒2(22.5×10+10×7.5+22.5×7.5) cm
2
=2×468.75=937.5 cm
2
⇒Area that can be painted by part of container =93750 cm
2
⇒Let x number of bricks will be used.
⇒Area =937.5×x cm
2
⇒x=
937.5
93750
⇒x=100
⇒Area=9.375m
2
⇒22.5cm×10cm×7.5cm=l×b×h
⇒Total surface of cuboid (brick) =2(lb+bh+lh)
⇒2(22.5×10+10×7.5+22.5×7.5) cm
2
=2×468.75=937.5 cm
2
⇒Area that can be painted by part of container =93750 cm
2
⇒Let x number of bricks will be used.
⇒Area =937.5×x cm
2
⇒x=
937.5
93750
⇒x=100
Answered by
0
Answer
Given:
⇒Area=9.375m
2
⇒22.5cm×10cm×7.5cm=l×b×h
⇒Total surface of cuboid (brick) =2(lb+bh+lh)
⇒2(22.5×10+10×7.5+22.5×7.5) cm
2
=2×468.75=937.5 cm
2
⇒Area that can be painted by part of container =93750 cm
2
⇒Let x number of bricks will be used.
⇒Area =937.5×x cm
2
⇒x=
937.5
93750
⇒x=100
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