Question

A can of tomatoes has a radius of 6 cm and a height of 10 cm. What is the approximate volume of the can?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Volume\:of\:can=1130.4\:cm^{3}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given: }} \\ \tt: \implies Radius \: of \: can = 6 \: cm \\ \\ \tt : \implies Height \: of \: can = 10 \: cm \\ \\ \red{\underline \bold{To \: Find: }} \\ \tt: \implies Volume \: of \: can = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Volume \: of \: can = \pi {r}^{2} h \\ \\ \tt: \implies Volume \: of \: can =3.14 \times {6}^{2} \times 10 \\ \\ \tt: \implies Volume \: of \: can =31.4 \times 36 \\ \\ \green{\tt: \implies Volume \: of \: can =1130.4 \: {cm}^{3} } \\ \\ \blue{ \bold{Some \: related \: formula}} \\ \orange{\tt\circ \: C.S.A \: of \: cylinder = 2\pi rh} \\ \\ \orange{\tt\circ \: T.S.A \: of \: cylinder = 2\pi r(h + r)}$

Answer 2

$\tt{\red{Solution \::- }}$

Question :

A can of tomatoes has a radius of 6 cm and a height of 10 cm.

What is the approximate volume of the can?

Solution :

$\tt{\orange {Step-By-Step-Explaination \::-}}$

Volume of A cone :

$\tt{ \purple{ \leadsto{Volume \: = \pi \: {r}^{2} h \: = 3.14 \times 36 \times 10 = \: 1130.4 \: {cm}^{3} }}}$

$\green{ \bold{Some \: related \: formula: }} \\ \orange{\tt\square\: C.S.A \: of \: cylinder = 2\pi rh} \\ \\ \orange{\tt\square \: T.S.A \: of \: cylinder = 2\pi r(h + r)}$