A can run 15 meters while b runs 20 metres. in a km race b beats a by
Answers
therefore ,by unitary method
15 m is run by a in r min
1 m is run by a in r/15 min
1000a m is run by a in r/15 × 1000a=200ra/3
20 m is run by b in r min
1 m is run by b in r/20 min
1000a m is run by a in r/20 × 1000a=50ra
time b beats a by 200ra/3-50ra
=50ra/3
Answer: Distance run by A = Speed of A * Time taken by B to run 1 km
= 750 meters
Step-by-step explanation:
To calculate how much time B beats A by in a 1 kilometer race, we need to first determine how many meters A can run in the same amount of time it takes B to run 1 kilometer. This can be calculated using the following formula:
Time taken by B to run 1 km = Distance / Speed
Since we know that B can run 20 meters, we can calculate his speed as follows:
Speed of B = Distance / Time taken by B = 20 meters / (1 kilometer / 1000 meters) = 20 meters per second
To find out how many meters A can run in the same amount of time, we can use the following formula:
Distance run by A = Speed of A * Time taken by B to run 1 km
Since we don't know A's speed, we need to calculate it using the ratio of their speeds:
Speed of A : Speed of B = 15 meters : 20 meters
Simplifying the ratio, we get:
Speed of A : Speed of B = 3 : 4
Therefore, A's speed is (3/4) * 20 = 15 meters per second.
Now we can use this speed to calculate how far A can run in the same time it takes B to run 1 kilometer:
Distance run by A = Speed of A * Time taken by B to run 1 km
= 15 meters per second * (1 kilometer / 20 meters per second)
= 750 meters
Therefore, B beats A by 1 kilometer - 750 meters = 250 meters in a 1 kilometer race.
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