Question

A can starts from reest
accelerates will
5-21 seconds
for 110m - Find Accelaration without using eq of
motion
​

Answer 1

Answer:

6.875 m/s²

Explanation:

Given:

• Initial velocity = u = 0 m/s
• Time taken = t = 21-5 = 16 seconds
• Final velocity = v = 110 m/s

To find:

• Acceleration of the car

Acceleration = (Final velocity-Initial velocity)/Time

Acceleration = (110-0)/16

Acceleration = 110/16

Acceleration = 6.875 m/s²

The acceleration of the car is equal to 6.875 m/s²

More:

• First equation of motion = V=u+at
• Second equation of motion = s = ut+1/2 at²
• Third equation of motion = v²-u²=2as

Answer 2

Answer:

6.875 m/s²

Explanation:

A car starts from rest means the initial velocity is 0 m/s.

Also given that finally velocity is 110 m/s in 5-21 sec.

First equation of motion is v = u + at

Second equation of motion is s = ut + 1/2 at²

Third equation of motion is v² - u² = 2as

As per given condition we have to find the acceleration without using equations of motion.

Acceleration = (Final velocity - Initial velocity)/(Final time - Initial time)

= (110 - 0)/(21 - 5)

= 110/16

= 6.875 m/s²

Hence, the acceleration of the car is 6.875 m/s².