Question

A can travels half of the distance with a constant
velocity of 40kmph and remaining half with a
constant velocity of 60kmph. The average velocity is .....?
[From Manipal exam 2005, Kerala CET 2005]​

Answer 1

Answer:

Let x be the distance travelled by the car..x/2 be half the distance now time t taken by the car with a velocity 40km/hr is x/80hr (time=distance/speed) time t taken by the car with a velocity 60km/hr is x/120 hr. 

now avg velocity= x/2+x/2

                           x/80+x/120

                          = x*9600

                                200x

                           = 48km/hr 

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Answer 2

Answer:

48m/s

Explanation:

let the total distance be x, so half of the distance is x/2 and remaining half is x/2.

the formula to find time is ( time= distance travel/ speed)

now the time required for the first half is (x/2) 40 = x/ 80

the time required to travel next half distance is (x/2)/60 = x/120

that is total time = x/80 + x/120

                           = x/48

now average speed = total distance / total time

                                 = x48/ x

                                 = 48 m/s