A can work 40% more than B. And B can work 20% less than C. If A take 9 days less than C to complete a work. Then how many days taken by B to complete that work.
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ANSWER= 60 days
A is 40℅ more efficient than B
efficiency of A:B = 140:100 = 7:5
B is 20℅ less efficient than C
efficiency of B:C = 80:100 = 4:5
hence,
efficiency of all =
A:B:C = 28:20:25
now, A takes 9 days less than C
hence..
28 - 25 = 3 unit = 9 days
so,
B takes 20× 9/3 = 60 days to complete the work.
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