Question

A can work twice as fast as B. A&C together can work three times as fast as B. If A,B&C complete the job in 30 days working together, in how many days can reach of them complete the work.

Answer 1

Let time taken by B to accomplish the work = x days

Then time taken by A to accomplish the work = $\frac{x}{2}$ days

Time taken by A and C to accomplish the work = $\frac{x}{3}$ days

Time taken by A, B and C jointly to accomplish the work = 30 days

(A+B+C) one day's work = $\frac{1}{30}$

(A+C) one day's work + B one day's work=  $\frac{1}{30}$

$\frac{3}{x}$ +  $\frac{1}{x}$=  $\frac{1}{30}$

$\frac{4}{x}$= $\frac{1}{30}$

x= 120 days

Time taken by B to accomplish the work alone = 120 days  

Time taken by A to accomplish the work alone = $\frac{x}{2}$ days=$\frac{120}{2}$= 60 days

Time taken by C to accomplish the work alone =(A+C) one day's work ($\frac{3}{x}$ )-  A's one days work

$=\frac{1}{40} -\frac{1}{60}= \frac{3-2}{120} = \frac{1}{120}$= 120 Days

A= 60 days, B= 120 days, C=120 days

Answer 2

Answer:

A=60

B=120

C=120

Step-by-step explanation:

b=x

x=120

a=60

c=120