Math, asked by riyanshi, 1 year ago

A canal is 300 cm wide and 120 cm deep, the water in the canal is flowing with a speed of 20 km/h. How much area will it irrigate in 20 min, if 8 cm of standing water is desirable?

Answers

Answered by ammy6
473
width 300cm=3m
depth 120cm=1.2m
speed of canal 20km/h
20×1000m/h
vol. of water flow in 1 hour = width of canal ×depth of canal ×speef of canal water
3×1.2×20×1000=72000m3
in 20 in vol. of water flows = 72000×20÷60=24000m3
area irrigated in 20 min 2400÷0.08=300000m2
30 hectare

riyanshi: thank u
Answered by vaishnavisarda2006
32

Answer:

Step-by-step explanation:

you can view the pic which i have added down

Attachments:
Similar questions