Question

A canal is 540 cm wide and 180 cm deep the water in the canal is flowing at the speed of 25 km per hour how much area will be will it irrigate in 40 minutes if 10 cm of standing water is desired

Answer 1

Answer:

3645000meter

Step-by-step explanation:

Volume of water flow in one hour =(5.4×1.8×25000)

Let the area of field irrigation=X.

(0.1×X×(40/60)) =(5.4×1.8×25000)

X=(5.4×1.8×25000) ÷(0.1×(40/60))

X=3645000meter

Answer 2

Irrigation Area is 56.25 Hectares

Step-by-step explanation:

The Volume of the water coming out in 1 hour of 6 m wide and 1.5 deep with speed of $10\ kmhr^-^1$ (Speed = $10 \times 1000\ mhr^-^1$)

= $6 \times 1.5 \times 10000$

= $90000 m^3$

therefore the volume of the water coming out in 30 min

= $90000 \times \frac {30}{60}$

Let the Area irrigated be $x\ m^2$

standing water height be $h = 8 cm = \frac {8}{100}$

= 0.08 m

Therefore, $x \times 0.08 = 45000$

or $x = \frac {45000}{0.08}$

= 56,2500 $m^2$

since 1 hectare = 10000 sq m

thus the area irrigated = 56.25 hectare