Math, asked by kriti730, 1 year ago

a cancer 75% of the problems in this book and we can solve 70% what is the probability that either​

Answers

Answered by GauravSaxena01
1

Answer:

a, probability of solving problem = 75%

=> \frac{75}{100} =  (3 X 25) / (4 X 25)

=>  3 / 4

a, probability of not solving problem = 1 - (\frac{3}{4})

=>\frac{1}{4}

b probability of solving problem = 70%

=> \frac{70}{100}

=> (7 X 10) / (10 X 10)

=> \frac7}{10}

b, probability of not solving problem

= 1 - (\frac7}{10})

=>  3 / 10

Now,

a or b solving a problem = a solves and b does not + a does not  and b does + Both a and b solves the problem

=> (\frac3}{4}) X (\frac3}{10}) + (\frac1}{4}) X (\frac7}{10}) + (\frac37}{4}) X (\frac7}{10})

=> (\frac9}{40}) + (\frac7}{40}) + (\frac21}{40})

=> \frac37}{40}

=> \frac37}{40}

X 100%

=> 37 X 2.5%

= > 92.5% or 0.925

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@GauravSaxena01

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