Question

A cand do a peice of work in 12 days and B can do it in 20 days. they work together for 3 days and then A goes away. in how many days will B finish the remaining work​

Answer 1

Answer:-

Time taken by A to do a piece of work= 12 days.

Hence One day work of A =

$\frac{1}{12}$

Time taken by B to finish the work= 20 days

Hence One day work of B =

$\frac{1}{20}$

Work done by together =

$\frac{1}{12} + \frac{1}{20}$

$\frac{10 + 6}{120}$

$\frac{16}{120}$

$\frac{2}{15}$

Work done by B =

$\frac{1}{12} - \frac{1}{20} + \frac{2}{15}$

$\frac{1}{12} - \frac{6 + 8}{120}$

$\frac{1}{12} - \frac{14}{120}$

$\frac{10 - 14}{120}$

$\frac{4}{120}$

$30$

B finish the remaining work in 30 days.

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