a candidate 21% marks in a test and failed by 10 marks. another candidate secured 42% and got half mark more than the minimum to pass. find the maximum mark.
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Answer: The maximum marks in the test is 50.
Step-by-step explanation:
Suppose, minimum passing marks=x
and maximum marks= y
Case 1: A candidate got 21% makes and failed by 10 marks.
According to the question,
21%y= x-10
=> 21y= 100x-1000 ......equation 1
Case 2: Another candidate secured 42% and got half marks more than the minimum passing marks.
According to the question,
42%y= x+1/2
=> 42y=100x+50 ........equation 2
Solving equation 1 and 2, we get
21y= 1050
y=50
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