A candidate appeared in three tests of the value of 20, 50 and 30 marks respectively. He obtained 75% marks in the first and 60% marks in the second test. What should be his percentage of marks in the third test if his aggregate percentage score is to be 60%?
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Given : Scored Marks in 1st test 75% out of 20.
Scored Marks in 2nd test 60% out of 50
Aggregate Percentage =60%
To Find : Marks in 3rd test
Solution :
Marks in 1st test = 75%×20 = 15
Marks in 2 nd Test =60 %×50 =30
Let Mark scored in 3 rd test be "x"
Aggregate Total Marks =60%×(sum of marks)
=60%×(20+50+30)
=60%×100
=60
Sum of All marks = Aggregate Marks
15 +30+x = 60
x =15
Percentage of 3rd marks =
actual /Aggregateof 3rd test ×100
=15/30×100
=50%
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