Math, asked by abhijain9112001, 1 year ago

A candidate has to obtain 33% of total marks to pass. He obtains 262 marks and fails by 200 marks and fails by 200 Mark's. Find the total marks.​

Answers

Answered by venupillai
3

Answer:

Total marks = 1386

Step-by-step explanation:

Let x = total marks

=> passing marks = x/3        (33% = 1/3)

ATQ,

The candidate gets 262 marks but fails by 200. This means he gets 200 marks less than passing marks.

262 = (x/3) - 200

262*3 = x - 200*3

786 = x - 600

x = 1386

Total marks = 1386

Verification:

Total marks = 1386 Passing marks = 1386/3 = 462

262 is 200 less than 462 (verified)

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