Question

A candidate is required to answer 6 out of 10 questions, which are divided into two groups each containing 5 questions, and he is not permitted to attempt more than 4 from each group. In how many ways can he make up his choice?

Answer 1

He can answer the questions in

6C4*6C2=15*15=225

6C3*6C3=20*20=400

6C2*6C4=25*15=225

=850

Answer 2

Answer: Our required ways = 200.

Step-by-step explanation:

Since we have given that

Number of total questions = 10

Number of questions he is required to answer = 6

So, total number of ways would be

$^{10}C_6\\\\=210$

Number of ways to attempt more than 4 from each group.

so, number of ways would be

$2\times ^5C_5\times ^5C_1\\\\=10$

so, Number of ways that he can make up his choice by not attempting more than 4 from each group is given by

$210-10\\\\=200$

Hence, our required ways = 200.