A candidate is selected for interview for 3 posts. For the first post, there are 3 candidates, for the second, 4 and for the third post there are 2 candidates. What is the probability that the candidate is selected for at least one post?
Answers
= (2/3)*(3/4)*(1/2)= 1/4
Probability that he selected for atleast 1 post = 1 -1/4 =3/4
probability that the candidate is selected for at least one post = 3/4
Step-by-step explanation:
Probability of selection for 1st post = 1/3
Probability of not selection for 1st post = 1 - 1/3 = 2/3
Probability of selection for 2nd post = 1/4
Probability of not selection for 2nd post = 1 - 1/4 = 3/4
Probability of selection for 3rd post = 1/2
Probability of not selection for 3rd post = 1 - 1/2 = 1/2
probability that the candidate is selected for at least one post = 1 - Probability that not selected for any post
= 1 - (2/3)(3/4)(1/2)
= 1 - 1/4
= 3/4
probability that the candidate is selected for at least one post = 3/4
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