Question

A candidate score 25% maeks and failed by 60 marks while the other candidate got 50% marks and got 40 marks more than the maximum marks required to pass..Find the total marks of the examination.Please answer step by step​

Answer 1

Solution:-

Let the maximum marks be 'x'.

Then, according to the question.

(25 % of x) + 30 = (50 % of x) - 20

⇒ x/4 + 30 = x/2 - 20

⇒ (x/4) - (x/2) = - 20 - 30

⇒ (x - 2x)/4 = - 50

⇒ - x/4 = - 50

⇒ - x = - 200

⇒ x = 200

So, the maximum marks are 200.

Minimum passing marks are = x/4 + 30

= 200/4 + 30

= 50 + 30

= 80 marks

Minimum passing marks are 80.

Answer.