Question

A candidate score 25% maeks and failed by 60 marks while the other candidate got 50% marks and got 40 marks more than the maximum marks required to pass..Find the total marks of the examination​

Answer 1

Answer:

Let maximum mark be x and minimum mark be y.

25% of maximum mark = (25/100)x = x/4 = y-30 ..............(1)

50% of maximum mark = (50/100)x = x/2 = y+20 ...........(2)

subtract eqn.(1) from eqn.(2), we get x/4 = 50 or x = 200

substituting value of x in eqn.(1), we get y = 80

hence maximum mark is 200 and minimum mark is 80

Step-by-step explanation:

please mark me as brainly

Answer 2

Answer:

Minimum passing marks are 80.

Step-by-step explanation:

Let the maximum marks be 'x'.

Then, according to the question.

(25 % of x) + 30 = (50 % of x) - 20

⇒ x/4 + 30 = x/2 - 20

⇒ (x/4) - (x/2) = - 20 - 30

⇒ (x - 2x)/4 = - 50

⇒ - x/4 = - 50

⇒ - x = - 200  

⇒ x = 200

So, the maximum marks are 200.

Minimum passing marks are = x/4 + 30

= 200/4 + 30

= 50 + 30

= 80 marks