Question

a candidate scored 25%marks in an examination and failed by 30 marks while another candidate who scored 50% marks more than the minimum pass marks find the maximum marks and minimum pass marks​

Answer 1

Step-by-step explanation:

let the maximum mark be =x

(25%of x )+30 =(50%of x )-20

* x/4 +30 =x/2-20

* (x-2x)/4 = -50

* -x /4 = -50

* -x =50×4 = -200

* x =200

So,the maximum mark are 200

Minimum passing marks are =x/4 +30

=200/4+30

=50+30=80 mark

Minimum passing marks are 80