Question

A candidate scored 25% marks in an examination and failed by 30 marks, while another candidate who scored 50% marks got 20 marks more than the minimum pass mark. Find the maximum and minimum pass marks.

Answer 1

let the minimum marks be x
So the first candidate scored x-30 marks
The second candidate scored x+20 marks
Now,
2×(25%)=50%
2(x-30)=(x+20)
2x-60=x+20
x=80marks
Minimum pass marks=80

Answer 2

a candidate score = 25% marks
failed by 30 marks
another candidate score =50% marks
passed by 20 marks

different of % = 25 %
" ". marks= 50
50/ 25 × 100= 200
30/100 × 200 =60
60 + 20 = 80