a candidate scored 25% marks in an examination and failed by 30 marks while another candidate who scored 50% marks got 20 marks more than minimum pass marks find the maximum marks and minimum pass marks
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full marks = x
pass marks= y
.25 of x = y - 30.
.50 of x = y +20
solving these equations, x = 200 marks
y= 80 marks
y in ters of x in %=80/200 = 40%
pass marks= y
.25 of x = y - 30.
.50 of x = y +20
solving these equations, x = 200 marks
y= 80 marks
y in ters of x in %=80/200 = 40%
raj9179:
thank you bro
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