Question

A candidate scored 25% media and failed by 30 marks while another candidate scored 50% marks and scored 20 marks more than the minimum pass marks. Find the maximum marks and minimum pass marks.

Answer 1

Let the maximum marks be x.
A/q
$\frac{25}{100}x + 30 = \frac{50}{100}x - 20 \\ \frac{25}{100} x - \frac{50}{100} x = - 20 - 30 \\ \frac{ - 25}{100}x = - 50$
$x = \frac{50 \times 100}{25} \\ x = 200$
Hence,the maximum marks required to pass exam is 200.