a candidate scored 25 percent marks in an examination and failed by 30 marks , while another candidate who scored 50 percent marks got 20 marks more than the minimum pass marks .Find the minimum pass marks and maximum marks
Answers
Answered by
8
HEY DEAR ... ✌️
______________________
______________________
Let the maximum marks be 'x'.
Then, according to the question.
(25 % of x) + 30 = (50 % of x) - 20
⇒ x/4 + 30 = x/2 - 20
⇒ (x/4) - (x/2) = - 20 - 30
⇒ (x - 2x)/4 = - 50
⇒ - x/4 = - 50
⇒ - x = - 200
⇒ x = 200
So, the maximum marks are 200.
Minimum passing marks are = x/4 + 30
= 200/4 + 30
= 50 + 30
= 80 marks
Minimum passing marks are 80.
HOPE , IT HELPS ... ✌️
______________________
______________________
Let the maximum marks be 'x'.
Then, according to the question.
(25 % of x) + 30 = (50 % of x) - 20
⇒ x/4 + 30 = x/2 - 20
⇒ (x/4) - (x/2) = - 20 - 30
⇒ (x - 2x)/4 = - 50
⇒ - x/4 = - 50
⇒ - x = - 200
⇒ x = 200
So, the maximum marks are 200.
Minimum passing marks are = x/4 + 30
= 200/4 + 30
= 50 + 30
= 80 marks
Minimum passing marks are 80.
HOPE , IT HELPS ... ✌️
Similar questions