Question

A candidate scores 46 percent and fails by 55 marks while another candidate scores 81 percent and gets 15 marks more than the minimum required marks to pass the exam. Find the maximum marks for the examination?
Select one:
a. 100
b. 200
c. 150
d. 350

Answer 1

Answer:

Option (b) 200

Step-by-step explanation:

Let the maximum marks be X

One candidate got 46% of X

Therefore the marks obtained by candidate = 0.46X

This is 55 marks less than the minimum marks

Hence, minimum marks = 0.46X + 55

Marks obtained by the other candidate = 0.81X

This is 15 marks more than the minimum marks

Thus, minimum marks = 0.81X - 15

Therefore,

0.46X + 55 = 0.81X - 15

or, 0.35X = 70

or, X = 70/0.35 = 7000/35 = 200

Thus, the maximum marks in the examination is 200

Hope this helps.

Answer 2

Answer:

Step-by-step explanation:

Assume the maximum marks for the examination is X

First candidate score 46% of the total so his marks = X × 46%

according to the question he fails by 55 marks so if we add 55 to his marks, he will pass.

So pass marks = X × 46% + 55  ---------------------------equation 1

While another candidate score = X × 81%

According to the question he gets 15 marks more than the passing marks so if we subtract 15 we get passing marks

so pass marks = X × 81% - 15  ------------------------------equation 2

We know the equation 1st is equal to the equation 2nd

Therefore

           X × 46% + 55 = X × 81% - 15

          X% (81 - 46) = 55 + 15

          35 × X% = 70

            X = 200

So maximum marks for the examination is 200