Question

A candidate scoring 50% in an examination fails by 60 marks, while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks. Find the minimum pass mark.​

Answer 1

The minimum $\sf p a s s$ mark is 260

Given :

• A candidate scoring 50% in an examination fails by 60 marks

• Another candidate scores 75 % mark, gets 40 marks more than the minimum $\sf p a s s$ marks

To find :

The minimum $\sf p a s s$ mark

Solution :

Step 1 of 5 :

Assume the total marks

Let total marks = 100x

Step 2 of 5 :

Find the minimum $\sf p a s s$ mark according to first candidate

First candidate scoring 50% in an examination fails by 60 marks

Marks obtained by the candidate = 50x

Minimum $\sf p a s s$ mark = 50x + 60

Step 3 of 5 :

Find the minimum $\sf p a s s$ mark according to second candidate

Second candidate scores 75% mark, gets 40 marks more than the minimum $\sf p a s s$ marks

Marks obtained by the candidate = 75x

Minimum $\sf p a s s$ mark = 75x - 40

Step 4 of 5 :

Find total marks

From the above

50x + 60 = 75x - 40

⇒ 50x - 75x = - 40 - 60

⇒ - 25x = - 100

⇒ x = 4

Thus total marks = 100 × 4 = 400

Step 5 of 5 :

Find minimum $\sf p a s s$ mark

Hence minimum $\sf p a s s$ mark

= 50x + 60

= ( 50 × 4 ) + 60

= 200 + 60

= 260

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