Question

A candidate who gets 20% marks fails by 10 marks, but another candidate who gets 42% marks get 12% marks more. Find the maximum marks. ​

Answer 1

Answer:

100

Step-by-step explanation:

let max marks be x

let fail mark be y

a boy got 20 % and failed by 10 marks

[(20/100) * x] + 10 = y

another boy got 42% and got 12% more than y

[(42 / 100) * x] - [(12/100) * x] = y

so, (20x / 100) +10 = (42x - 12x)/100

20x + 1000 = 30x

10x = 1000

x = 100