Question

A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.

Answer 1

Solutions :-


Given :
A candidate who gets 20% marks fails by 10 marks.
Another candidate who gets 42% marks gets 12% more than the passing marks.

Let the maximum marks be x


A/q

=> 20% of x + 10 = 42% of x - 12% of x
=> 0.20 × x + 10 = 0.42 × x - 0.12 of x
=> 0.20x + 10 = 0.42x - 0.12x
=> 0.20x + 10 = 0.30x
=> 0.30x - 0.20x = 10
=> 0.10x = 10
=> x = 10/0.10 = 100


Hence,
The Maximum marks = 100

Answer 2

Here is your solutions

Given that :-

➡A candidate who gets 20% .

➡marks fails by 10 marks.

➡Another candidate who gets 42% marks.

➡And gets 12% more than the passing marks.

TO FIND THE MAXIMUM MARKS :-

Let the maximum marks be x

According to question

=> 20% of x + 10 = 42% of x - 12% of x

=> 0.20 × x + 10 = 0.42 × x - 0.12 of x

=> 0.20x + 10 = 0.42x - 0.12x

=> 0.20x + 10 = 0.30x

=> 0.30x - 0.20x = 10

=> 0.10x = 10

=> x = 10/0.10

=> x = 10×100/10

=>x = 100

Hence,

The Maximum marks is 100

Hope it helps you