A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing?
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12
let the total marks be x
x × 30% /100 + 50= x × 45% / 100+25
30x /100 + 50 = 45x/100 + 25
50-25 = 45x /100 - 30x /100
25 = 15x /100
15x =25 × 100
x = 25 × 100 /15
x = 500/3
total marks to pass
500/3 × 30/100 +50
50 + 50
100 marks
x × 30% /100 + 50= x × 45% / 100+25
30x /100 + 50 = 45x/100 + 25
50-25 = 45x /100 - 30x /100
25 = 15x /100
15x =25 × 100
x = 25 × 100 /15
x = 500/3
total marks to pass
500/3 × 30/100 +50
50 + 50
100 marks
BhawnaAggarwalBT:
please count it as brillianes guestions
Answered by
21
Hey.
Here is the answer.
Let passing marks be x and total marks be T
So, 30% of T + 50 = x
or, 0.30 T + 50 = x __________1st eqn
Also, 45 % of T -25 = x
or, 0.45 T - 25 = x ____________2nd eqn
After solving 1st and 2nd eqn ;
Total marks T = 500 marks
Passing marks x = 200 marks
Thanks .
Here is the answer.
Let passing marks be x and total marks be T
So, 30% of T + 50 = x
or, 0.30 T + 50 = x __________1st eqn
Also, 45 % of T -25 = x
or, 0.45 T - 25 = x ____________2nd eqn
After solving 1st and 2nd eqn ;
Total marks T = 500 marks
Passing marks x = 200 marks
Thanks .
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