A candidate who gets 36% marks in an examination fails by 24 marks but anotheranother candidate who gets 43% marks get 18 more marks than the minimum pass marks .Find the maximum marks and the percentage of pass marks.
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Step-by-step explanation:
Let the total marks be x
Pass marks =
36%of x+24 = 43%of x-18
=>7% of x =42
=>7*x/100=42
=>x=42*10/7
=>x=600
Pass marks= 36% of x+24
=36*600/100 +24
=240
Pass percentage= 240*100/600
=40%
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